Results 11 to 20 of about 230 (49)

Implications between approximate convexity properties and approximate Hermite-Hadamard inequalities

Open Mathematics, 2012
In this paper, the connection between the functional inequalities $$ f\Big(\frac{x+y}{2}\Big)\leq\frac{f(x)+f(y)}{2}+\alpha_J(x-y) \qquad (x,y\in D)$$ and $$ \int_0^1f\big(tx+(1-t)y\big)\rho(t)dt \leq\lambda f(x)+(1-\lambda)f(y) +\alpha_H(x-y) \qquad (x ...
Makó Judit, Páles Zsolt
doaj   +2 more sources

Anti-Saccharomyces cerevisiae antibodies in patients with inflammatory bowel disease and their first-degree relatives: Potential clinical value [PDF]

, 2002
Anti-Saccharomyces cerevisiae antibodies (ASCA) have been described as specific markers in Crohn's disease and their healthy first-degree relatives. 171 patients with Crohn's disease, their 105 first-degree relatives, 145 patients with ulcerative colitis
Folwaczny, Christian, Glas, J., Herbinger, K. H., Hoelscher, Michael, Török, H.-P., Vilsmaier, F.   +5 more
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Response to combination therapy with interferon alfa-2a and ribavirin in chronic hepatitis C according to a TNF-alpha promoter polymorphism [PDF]

, 2003
Background. Tumor necrosis factor-alpha (TNF-alpha) is involved in the pathogenesis of chronic active hepatitis C. Polymorphisms in the promoter region of the TNF-alpha gene can alter the TNF-alpha expression and modify the host immune response.
Folwaczny, Christian, Glas, J., Konig, A., Martin, K., Schaefer, M., Schiemann, Uwe, Schmidt, F., Simperl, C., Torok, P.   +8 more
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A composite functional equation from algebraic aspect [PDF]

, 2013
In this paper we discuss the composite functional equation f(x+2f(y))=f(x)+y+f(y) on an Abelian group. This equation originates from Problem 10854 of the American Mathematical Monthly.
A. Gilányi, Attila Házy, D. Henderson, Gy. Maksa, J. Matkowski, J. Okrzesik, J. Rätz, Pál Burai, T. Kochanek, Tibor Juhász, W. Fechner, Z. Boros, Z. Daróczy, Zs. Páles   +13 more
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Approximate Hermite-Hadamard type inequalities for approximately convex functions [PDF]

, 2012
In this paper, approximate lower and upper Hermite--Hadamard type inequalities are obtained for functions that are approximately convex with respect to a given Chebyshev ...
Makó, Judit, Páles, Zsolt
core   +1 more source

Around a problem of Nicole Brillouët–Belluot [PDF]

, 2013
We determine nontrivial intervals I ⊂ (0,+∞), numbers α ∈ R and continuous bijections f : I → I such that f(x)f−1(x) = xα for every x ...
C.T. Ng, J. Morawiec, J.L. Massera, Janusz Morawiec, L. Chen, M. Kuczma, M. Kuczma, N. Brillouët–Belluot, R. Anschuetz, R. Cheng, R. Euler, U. Daepp, W. Jarczyk   +12 more
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Dilated Floor Functions That Commute

, 2016
We determine all pairs of real numbers $(\alpha, \beta)$ such that the dilated floor functions $\lfloor \alpha x\rfloor$ and $\lfloor \beta x\rfloor$ commute under composition, i.e., such that $\lfloor \alpha \lfloor \beta x\rfloor\rfloor = \lfloor \beta
Lagarias, Jeffrey C., Murayama, Takumi, Richman, D. Harry   +2 more
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Permutable entire functions satisfying algebraic differential equations

, 2005
It is shown that if two transcendental entire functions permute, and if one of them satisfies an algebraic differential equation, then so does the other one.Comment: 5 ...
A E Eremenko, A Ostrowski, C-C Yang, F Gross, F Gross, F Gross, G Julia, G Pólya, I N Baker, J Clunie, J F Ritt, J H Zheng, J H Zheng, J H Zheng, J H Zheng, N Steinmetz, P Fatou, T Kobayashi, T W Ng, W D Brownawell, W K Hayman, W Xiong   +21 more
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On a problem of Janusz Matkowski and Jacek Wesołowski [PDF]

, 2018
We study the problem of the existence of increasing and continuous solutions φ :[0 , 1] → [0 , 1] such that φ (0) = 0 and φ (1) = 1 of the functional equation φ ( x )= N ∑ n =0 φ ( f n ( x )) − N ∑ n =1 φ ( f n (0)) , where N ∈ N and f 0 ,...,f N
Morawiec, Janusz, Zürcher, Thomas
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Multi-variable translation equation which arises from homothety

, 2010
In many regular cases, there exists a (properly defined) limit of iterations of a function in several real variables, and this limit satisfies the functional equation (1-z)f(x)=f(f(xz)(1-z)/z); here z is a scalar and x is a vector. This is a special case
A. Mach, B. Przebieracz, Giedrius Alkauskas, H. Fripertinger, K. Baron, K. Baron, L. Berg, Z. Moszner, Z. Moszner   +8 more
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