Results 51 to 60 of about 83 (64)
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Further Berezin Number and Berezin Norm Inequalities for Sums and Products of Operators
Complex Analysis and Operator TheoryzbMATH Open Web Interface contents unavailable due to conflicting licenses.
Kallol Paul +2 more
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Berezin Number and Norm Inequalities for Operators in Hilbert and Semi-Hilbert Spaces
Mathematics Online First Collections, 2023Kais Feki +2 more
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Inequalities related to Berezin norm and Berezin number of operators
2022Summary: The Berezin symbol \(\widetilde{A}\) of an operator \(A\) on the reproducing kernel Hilbert space \(\mathcal{H}(\Omega)\) over some set \(\Omega\) with the reproducing kernel \(k_\lambda\) is defined by \[ \widetilde{A}(\lambda) = \left\langle A \widehat{k}_\lambda,\widehat{k}_\lambda \right\rangle,\; \lambda \in \Omega.
Basaran, Hamdullah +2 more
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Schatten-Herz Operators, Berezin Transform and Mixed Norm Spaces
Integral Equations and Operator Theory, 2011Let ...
Blasco, Oscar, Pérez-Esteva, Salvador
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Some estimations of the Berezin radius and the Berezin norm
Rendiconti del Circolo Matematico di Palermo Series 2zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Bakherad, Mojtaba, Kittaneh, Fuad
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Norm of Berezin transformon L p space
Journal d'Analyse Mathématique, 2008Let \(D\) be the unit disc in \(\mathbb C\) equipped with the standard Lebesgue measure \(\mu\). For \(K_\alpha(z, \xi)= (\alpha +1)\frac{(1-| \xi| ^2)^\alpha}{^(1-z\overline{\xi})^{\alpha + 2}}\), the operator \(G_\alpha: L^p(D) \to L^p(D)\), \((G_\alpha f)(z):= \frac1\pi \int_D| K_\alpha(z, \xi)| f(\xi)\,d\mu(\xi)\) is introduced.
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New estimates for the Berezin number and Berezin norm
This paper intends to establish several inequalities employing the Cartesian decomposition of the operator. We used the results to determine the Berezin number inequalities. Our results extend and improve some earlier inequalities.Nourbakhsh, S. +3 more
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The Berezin Number, Norm of a Hankel Operator and Related Topics
2015We give, in terms of the Berezin number, necessary and sufficient conditions providing unitarity of an invertible operator. Also we obtain in terms of the Berezin number a new inequality for the norm of the Hankel operator \(H_{\varphi}\) which is better than the classical inequality \(\|H_{\varphi}\|\leq\|\varphi\|_{\infty}\) The Berezin number is ...
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The Berezin radius and the Berezin norm associated with the tensor product
Operators and MatricesMojtaba Bakherad, Mubariz T. Garayev
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Development of the Berezin Number Inequalities
Acta Mathematica Sinica, English Series, 2023Kallol Paul +2 more
exaly

