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Berezin number and Berezin norm inequalities for operator matrices [PDF]
We establish new upper bounds for Berezin number and Berezin norm of operator matrices, which are refinements of the existing bounds. Among other bounds, we prove that if $A=[A_{ij}]$ is an $n\times n$ operator matrix with $A_{ij}\in\mathbb{B}(\mathcal{H})$ for $i,j=1,2\dots n$, then $\|A\|_{ber} \leq \left\|\left[\|A_{ij}\|_{ber}\right]\right\|$ and $
Kallol Paul, Pintu Bhunia, Anirban Sen
exaly +4 more sources
Inequalities Involving Berezin Norm and Berezin Number
We obtain new inequalities involving Berezin norm and Berezin number of bounded linear operators defined on a reproducing kernel Hilbert space $\mathscr{H}.$ Among many inequalities obtained here, it is shown that if $A$ is a positive bounded linear operator on $\mathscr{H}$, then $\|A\|_{ber}=\textbf{ber}(A)$, where $\|A\|_{ber}$ and $\textbf{ber}(A)$
Kallol Paul, Pintu Bhunia, Anirban Sen
exaly +3 more sources
Development of the Berezin Number Inequalities
We present new bounds for the Berezin number inequalities which improve on the existing bounds. We also obtain bounds for the Berezin norm of operators as well as the sum of two operators.
Kallol Paul, Pintu Bhunia, Anirban Sen
exaly +3 more sources
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On Berezin Number Inequalities for Operator Matrices
Acta Mathematica Sinica, English Series, 2021For a bounded linear operator, acting in the reproducing kernel Hilbert space \(\mathcal{H}=\mathcal{H}(\Omega)\) over some set \(\Omega\), its Berezin symbol \(\tilde{A}\) is defined by \(\tilde{A}(\lambda)=\langle A\tilde{k}_\lambda, \tilde{k}_\lambda \rangle\), where \(\tilde{k}_\lambda\) the normalized reproducing kernel of \(\mathcal{H}\).
Satyajit Sahoo +2 more
exaly +2 more sources
Refinements of some inequalities involving Berezin norms and Berezin number and related questions
Annali Dell'Universita Di Ferrara, 2023zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Mubariz Garayev
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Berezin Number and Numerical Radius Inequalities
Vietnam Journal of Mathematics, 2023zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Anirban Sen, Kallol Paul
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Berezin number and Berezin norm inequalities via Moore-Penrose inverse
In this article, we establish the Berezin number and Berezin norm inequalities for bounded linear operators on a reproducing kernel Hilbert space using the Moore-Penrose inverse. The inequalities obtained here refine and generalize the earlier inequalities.
Kallol Paul, Anirban Sen
exaly +3 more sources
Inequalities related to Berezin norm and Berezin number of operators
2022Summary: The Berezin symbol \(\widetilde{A}\) of an operator \(A\) on the reproducing kernel Hilbert space \(\mathcal{H}(\Omega)\) over some set \(\Omega\) with the reproducing kernel \(k_\lambda\) is defined by \[ \widetilde{A}(\lambda) = \left\langle A \widehat{k}_\lambda,\widehat{k}_\lambda \right\rangle,\; \lambda \in \Omega.
Basaran, Hamdullah +2 more
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The weighted and the Davis-Wielandt Berezin number
Operators and Matrices, 2023Summary: A functional Hilbert space is the Hilbert space of complex-valued functions on some set \(\Theta \subseteq \mathbb{C}\) that the evaluation functionals \(\varphi_\lambda (f) = f\ (\lambda)\), \(\lambda \in \Theta\) are continuous on \(\mathcal{H}\). The Berezin number of an operator \(T\) is defined by \(\mathbf{ber} (T) =\sup\limits_{\lambda \
Garayev, Mubariz T. +2 more
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Further Berezin Number and Berezin Norm Inequalities for Sums and Products of Operators
Complex Analysis and Operator TheoryzbMATH Open Web Interface contents unavailable due to conflicting licenses.
Guesba, Messaoud +2 more
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