Results 21 to 30 of about 259 (129)
On the endomorphism monoids of Clifford semigroups
, 2018 In this paper, we study properties of the endomorphism monoids of strong semilattices of groups. In Sec. 2, several properties for endomorphism monoids of finite semilattices are investigated. In Sec.
Somnuek Worawiset
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Semigroup endomorphisms of rings [PDF]
Journal of the Australian Mathematical Society, 1978 AbstractWe show that rings for which every non-constant multiplicative endomorphism is additive are trivial or power rings (that is, rings R such that R = R2 and x2 = 0 = x+x for all x ∈ R) and that if R is a power ring for which every multiplicative endomorphism is additive, then End (R) is a zero semigroup or a semilattice according to how the ...
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F1000ResearchThroughout this paper our study focuses on transformation semigroups. These kinds of semigroups are the corner stone of semigroup theory. This is because every semigroup is isomorphic to transformation semigroup.
Asawer Al-Aadhami, Hala M. Sulaiman
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F1000ResearchThroughout this paper our study focuses on transformation semigroups. These kinds of semigroups are the corner stone of semigroup theory. This is because every semigroup is isomorphic to transformation semigroup.
Asawer Al-Aadhami, Hala M. Sulaiman
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Isotopy and equivalence of knots in 3‐manifolds
Journal of the London Mathematical Society, Volume 113, Issue 6, June 2026.Abstract Two knots K$K$ and J$J$ in S3$S^3$ are isotopic if and only if they are related by an orientation‐preserving diffeomorphism of S3$S^3$. This claim follows from the fact that any orientation‐preserving self‐diffeomorphism of S3$S^3$ is isotopic to the identity. We show that this same idea applies to any prime oriented closed 3‐manifold.
Paolo Aceto +4 more
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Endomorphisms of Finite Symmetric Inverse Semigroups
Journal of Algebra, 1997 Denote by \({\mathcal I}_n\) the symmetric inverse semigroup on \(X=\{1,2,\dots,n\}\). For any function \(f\), the rank of \(f\) is denoted by \(\text{rank}(f)\) and is the cardinality of the range of \(f\). For \(1\leq k\leq n+1\), let \(I_k=\{t\in{\mathcal I}_n:\text{rank}(t)2\) and \(n\neq 4\). If \(\varphi\) is an endomorphism of \({\mathcal I}_n\)
Schein, Boris M., Teclezghi, Beimnet
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Conformal optimization of eigenvalues on surfaces with symmetries
Journal of the London Mathematical Society, Volume 112, Issue 6, December 2025.Abstract Given a conformal action of a discrete group on a Riemann surface, we study the maximization of Laplace and Steklov eigenvalues within a conformal class, considering metrics invariant under the group action. We establish natural conditions for the existence and regularity of maximizers. Our method simplifies the previously known techniques for
Denis Vinokurov
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On endomorphisms of the bicyclic semigroup and the extended bicyclic semigroup
Visnyk Lvivskogo Universytetu Seriya Mekhaniko-Matematychna, 2021 It is proved that the semigroups $\mathrm{\mathbf{End}}(\boldsymbol{B}_ω)$ and $\mathrm{\mathbf{End}}(\boldsymbol{B}_{\mathbb{Z}})$ of the endomorphisms of the bicyclic semigroup $\boldsymbol{B}_ω$ and the endomorphisms of the extended bicyclic semigroup $\boldsymbol{B}_{\mathbb{Z}}$ are isomorphic to the semidirect products $(ω,+)\rtimes_φ(ω,*)$ and $\
Gutik, Oleg +2 more
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Is every product system concrete?
Transactions of the London Mathematical Society, Volume 12, Issue 1, December 2025.Abstract Is every product system of Hilbert spaces over a semigroup P$P$ concrete, that is, isomorphic to the product system of an E0$E_0$‐semigroup over P$P$? The answer is no if P$P$ is discrete, cancellative and does not embed in a group. However, we show that the answer is yes for a reasonable class of semigroups.
S. Sundar
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Continuous spatial semigroups of *-endomorphisms of 𝔅(ℌ) [PDF]
Transactions of the American Mathematical Society, 1990 To each continuous semigroup of ...
Robert T. Powers, Geoffrey Price
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