Results 11 to 20 of about 1,403,825 (285)

Slightly \gamma-Continuous Functions

open access: yesBoletim da Sociedade Paranaense de Matemática, 2009
The purpose of this paper is to give a new weak form of some typesof continuity generalizing strongly alpha-irresoluteness, alpha-irresoluteness, alpha-continuity, precontinuity, semi-continuity, gamma-continuity and slightly continuity. In this paper, slightly gama-continuity is introduced and studied.
EKİCİ, ERDAL, Caldas, M.
openaire   +4 more sources

Integral Representations of a Generalized Linear Hermite Functional

open access: yesMathematics, 2023
In this paper, we find new integral representations for the generalized Hermite linear functional in the real line and the complex plane. As an application, new integral representations for the Euler Gamma function are given.
Roberto S. Costas-Santos
doaj   +1 more source

Artin formalism for Selberg zeta functions of co-finite Kleinian groups [PDF]

open access: yes, 2008
Let $\Gamma\backslash\mathbb H^3$ be a finite-volume quotient of the upper-half space, where $\Gamma\subset {\rm SL}(2,\mathbb C)$ is a discrete subgroup.
Brenner, Eliot, Spinu, Florin
core   +2 more sources

A Ces\`aro Average of Goldbach numbers [PDF]

open access: yes, 2012
Let $\Lambda$ be the von Mangoldt function and $(r_G(n) = \sum_{m_1 + m_2 = n} \Lambda(m_1) \Lambda(m_2))$ be the counting function for the Goldbach numbers. Let $N \geq 2$ be an integer.
Languasco, Alessandro   +1 more
core   +1 more source

On Complex Gamma-Function Integrals [PDF]

open access: yesSymmetry, Integrability and Geometry: Methods and Applications, 2020
It was observed recently that relations between matrix elements of certain operators in the ${\rm SL}(2,\mathbb R)$ spin chain models take the form of multidimensional integrals derived by R.A. Gustafson. The spin magnets with ${\rm SL}(2,\mathbb C)$ symmetry group and ${\rm L}_2(\mathbb C)$ as a local Hilbert space give rise to a new type of ...
Derkachov, Sergey E.   +1 more
openaire   +4 more sources

On Gamma Function Inequalities [PDF]

open access: yesMathematics of Computation, 1986
We show that certain functions involving quotients of gamma functions are completely monotonic. This leads to inequalities involving gamma functions. We also establish the infinite divisibility of several probability distributions whose Laplace transforms involve quotients of gamma functions.
Bustoz, Joaquin, Ismail, Mourad E. H.
openaire   +2 more sources

Monotonicity and inequalities for the gamma function

open access: yesJournal of Inequalities and Applications, 2017
In this paper, by using the monotonicity rule for the ratio of two Laplace transforms, we prove that the function x ↦ 1 24 x ( ln Γ ( x + 1 / 2 ) − x ln x + x − ln 2 π ) + 1 − 120 7 x 2 $$ x\mapsto \frac{1}{24x ( \ln \Gamma ( x+1/2 ) -x\ln x+x- \ln \sqrt{
Zhen-Hang Yang, Jing-Feng Tian
doaj   +1 more source

Evaluation of the real parts of polylogarithm expressions containing complex arguments via certain logarithmic integrals [PDF]

open access: yesNotes on Number Theory and Discrete Mathematics
We consider a polylogarithm expression containing complex arguments, namely 𝓟±(n)=ℜ(Liₙ((1±i)/2)). The central notion of the present paper is to evaluate the real parts of 𝓟±(n) for first four orders, specifically n = 1,2,3, and 4, by constructing ...
Narendra Bhandari
doaj   +1 more source

Recurrent identities for two special functions of hypergeometric type

open access: yesВестник Самарского университета: Естественнонаучная серия, 2023
The article presents conclusions and proofs of Gauss-type identities for two known hypergeometric type functions. For the derivation and justification of formulas, the representation of functions in the form of a series is used, as well as an integral ...
Svetlana V. Podkletnova
doaj   +1 more source

On approximating the modified Bessel function of the second kind

open access: yesJournal of Inequalities and Applications, 2017
In the article, we prove that the double inequalities π e − x 2 ( x + a ) < K 0 ( x ) < π e − x 2 ( x + b ) , 1 + 1 2 ( x + a ) < K 1 ( x ) K 0 ( x ) < 1 + 1 2 ( x + b ) $$ \frac{\sqrt{\pi}e^{-x}}{\sqrt{2(x+a)}}< K_{0}(x)< \frac{\sqrt{\pi }e^{-x}}{\sqrt ...
Zhen-Hang Yang, Yu-Ming Chu
doaj   +1 more source

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