Results 21 to 30 of about 64,068 (309)

Trends, Cycles and Seasonal Variations of Ukrainian Gross Domestic Product [PDF]

open access: yesFinancial Markets, Institutions and Risks, 2020
The article attempts to study trends, seasonal variations and cyclical fluctuations of Ukraine’s quarterly GDP at current prices. The period of the study is from the first quarter of 2010 to the first quarter of 2020.
Debesh Bhowmik
doaj   +1 more source

Matchings and Hamilton cycles in hypergraphs [PDF]

open access: yesDiscrete Mathematics & Theoretical Computer Science, 2005
It is well known that every bipartite graph with vertex classes of size $n$ whose minimum degree is at least $n/2$ contains a perfect matching. We prove an analogue of this result for uniform hypergraphs. We also provide an analogue of Dirac's theorem on
Daniela Kühn, Deryk Osthus
doaj   +1 more source

Symmetric Hamilton Cycle Decompositions of Complete Multigraphs

open access: yesDiscussiones Mathematicae Graph Theory, 2013
Let n ≥ 3 and ⋋ ≥ 1 be integers. Let ⋋Kn denote the complete multigraph with edge-multiplicity ⋋. In this paper, we show that there exists a symmetric Hamilton cycle decomposition of ⋋K2m for all even ⋋ ≥ 2 and m ≥ 2.
Chitra V., Muthusamy A.
doaj   +1 more source

Removable Edges on a Hamilton Cycle or Outside a Cycle in a 4-Connected Graph

open access: yesDiscussiones Mathematicae Graph Theory, 2021
Let G be a 4-connected graph. We call an edge e of G removable if the following sequence of operations results in a 4-connected graph: delete e from G; if there are vertices with degree 3 in G− e, then for each (of the at most two) such vertex x, delete ...
Wu Jichang   +3 more
doaj   +1 more source

Polychromatic Hamilton cycles

open access: yesDiscrete Mathematics, 1993
If the complete graph on \(n\) vertices is edge-colored such that the number of times that a color may occur is less than \(cn/\log(n)\), where \(c\) is a fixed constant, then there is a Hamiltonian cycle in which no two edges have the same color.
Frieze, Alan, Reed, Bruce
openaire   +1 more source

Hamilton-connected properties in cartesian product [PDF]

open access: yesTransactions on Combinatorics, 2012
In this paper, we investigate a problem of finding natural condition to assure the product of two graphs to be hamilton-connected. We present some sufficient and necessary conditions for $GBox H$ being hamilton-connected when $G$ is a hamilton-connected ...
Rushengul Hoshur, Elkin Vumar
doaj  

Pancyclicity when each Cycle Must Pass Exactly k Hamilton Cycle Chords

open access: yesDiscussiones Mathematicae Graph Theory, 2015
It is known that Θ(log n) chords must be added to an n-cycle to produce a pancyclic graph; for vertex pancyclicity, where every vertex belongs to a cycle of every length, Θ(n) chords are required.
Affif Chaouche Fatima   +2 more
doaj   +1 more source

Rainbow Hamilton Cycles in Uniform Hypergraphs [PDF]

open access: yesThe Electronic Journal of Combinatorics, 2012
Let $K_n^{(k)}$ be the complete $k$-uniform hypergraph, $k\ge3$, and let $\ell$ be an integer such that $1\le \ell\le k-1$ and $k-\ell$ divides $n$. An $\ell$-overlapping Hamilton cycle in $K_n^{(k)}$ is a spanning subhypergraph $C$ of  $K_n^{(k)}$  with $n/(k-\ell)$ edges and such that for some cyclic ordering of the vertices each edge of $C$ consists
Dudek, Andrzej   +2 more
openaire   +2 more sources

Edge condition for hamiltonicity in balanced tripartite graphs [PDF]

open access: yesOpuscula Mathematica, 2009
A well-known theorem of Entringer and Schmeichel asserts that a balanced bipartite graph of order \(2n\) obtained from the complete balanced bipartite \(K_{n,n}\) by removing at most \(n-2\) edges, is bipancyclic.
Janusz Adamus
doaj   +1 more source

Perfect Set of Euler Tours of Kp,p,p

open access: yesDiscussiones Mathematicae Graph Theory, 2016
Bermond conjectured that if G is Hamilton cycle decomposable, then L(G), the line graph of G, is Hamilton cycle decomposable. In this paper, we construct a perfect set of Euler tours for the complete tripartite graph Kp,p,p for any prime p and hence ...
Govindan T., Muthusamy A.
doaj   +1 more source

Home - About - Disclaimer - Privacy