Results 21 to 30 of about 3,218,251 (319)
Minimum degree conditions for tight Hamilton cycles [PDF]
We develop a new framework to study minimum d$d$ ‐degree conditions in k$k$ ‐uniform hypergraphs, which guarantee the existence of a tight Hamilton cycle.
R. Lang, Nicolás Sanhueza-Matamala
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Edge Disjoint Hamilton Cycles in Knödel Graphs [PDF]
The vertices of the Knödel graph $W_{\Delta, n}$ on $n \geq 2$ vertices, $n$ even, and of maximum degree $\Delta, 1 \leq \Delta \leq \lfloor log_2(n) \rfloor$, are the pairs $(i,j)$ with $i=1,2$ and $0 \leq j \leq \frac{n}{2} -1$.
Palanivel Subramania Nadar Paulraja +1 more
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Finding Hamilton cycles in random intersection graphs [PDF]
The construction of the random intersection graph model is based on a random family of sets. Such structures, which are derived from intersections of sets, appear in a natural manner in many applications. In this article we study the problem of finding a
Katarzyna Rybarczyk
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A Note on Color-Bias Hamilton Cycles in Dense Graphs
Balogh, Csaba, Jing, and Pluhar [Electron. J. Combin., 27 (2020)] recently determined the minimum degree threshold that ensures a 2-colored graph $G$ contains a Hamilton cycle of significant color ...
Andrea Freschi +3 more
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Packing Hamilton Cycles Online [PDF]
It is known that w.h.p. the hitting time τ2σ for the random graph process to have minimum degree 2σ coincides with the hitting time for σ edge-disjoint Hamilton cycles [4, 9, 13]. In this paper we prove an online version of this property. We show that, for a fixed integer σ ⩾ 2, if random edges of Kn are presented one by one then w.h.p.
Briggs, Joseph +4 more
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Have Business Cycles Become More Synchronous After NAFTA?
Trade agreements do not necessitate business cycle comovement. Focusing on NAFTA, we investigate whether business cycles in Canada, Mexico, and the US have become more synchronous after the landmark trade agreement came into effect in 1994.
Puneet Vatsa
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Packing Loose Hamilton Cycles [PDF]
A subsetCof edges in ak-uniform hypergraphHis aloose Hamilton cycleifCcovers all the vertices ofHand there exists a cyclic ordering of these vertices such that the edges inCare segments of that order and such that every two consecutive edges share exactly one vertex.
Ferber, Asaf +3 more
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Extending Cycles Locally to Hamilton Cycles [PDF]
A Hamilton circle in an infinite graph is a homeomorphic copy of the unit circle $S^1$ that contains all vertices and all ends precisely once. We prove that every connected, locally connected, locally finite, claw-free graph has such a Hamilton circle, extending a result of Oberly and Sumner to infinite graphs.
Hamann, Matthias +2 more
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Identifying Hamilton cycles in the Cartesian product of directed cycles
Let be a Cartesian product of directed cycles. It is known that has a Hamilton cycle if there is a permutation of that satisfies and for some positive integers , where . In addition, if then has two arc-disjoint Hamilton cycles.
Zbigniew R. Bogdanowicz
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On powers of tight Hamilton cycles in randomly perturbed hypergraphs [PDF]
For integers k≥3$$ k\ge 3 $$ and r≥2$$ r\ge 2 $$ , we show that for every α>0$$ \alpha >0 $$ , there exists ε>0$$ \varepsilon >0 $$ such that the union of k$$ k $$ ‐uniform hypergraph on n$$ n $$ vertices with minimum codegree at least αn$$ \alpha n ...
Yulin Chang, Jie Han, L. Thoma
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