Results 281 to 290 of about 79,501 (322)
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Derivations on Banach-Jordan Pairs
The Quarterly Journal of Mathematics, 2001A classical topic in the theory of Banach structures is the automatical continuity of derivations. From 1968, when Johnson and Sinclair proved the continuity of derivations acting on semisimple associative Banach algebras, until now, several algebraic conditions on a Banach algebra \(A\) which ensure the continuity of its derivations have been ...
Fernández López, A. +2 more
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Jordan Higher Derivations of Incidence Algebras
Bulletin of the Malaysian Mathematical Sciences Society, 2021zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Lizhen Chen, Zhankui Xiao
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Nonlinear *-Jordan-type derivations on *-algebras
Rocky Mountain Journal of Mathematics, 2021zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Li, Changjing +2 more
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Mixed *-Jordan-type derivations on *-algebras
Journal of Algebra and Its Applications, 2022Let [Formula: see text] be an *-algebra with identity [Formula: see text] and [Formula: see text] and [Formula: see text] nontrivial symmetric idempotents in [Formula: see text]. In this paper we study the characterization of nonlinear mixed *-Jordan-type derivations.
Ferreira, Bruno Leonardo Macedo +1 more
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Characterizations of Jordan derivations and Jordan homomorphisms
Linear and Multilinear Algebra, 2011Let 𝒜 be a unital Banach algebra and ℳ be a unital 𝒜-bimodule. We show that if δ is a linear mapping from 𝒜 into ℳ satisfying δ(ST) = δ(S)T +Sδ(T) for any S, T ∈ 𝒜 with ST = W, where W is a left or right separating point of ℳ, then δ is a Jordan derivation.
Jiankui Li, Jiren Zhou
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1994
A classical nonassociative operators topic is the continuity of Jordan derivations on Banach algebras which have some aditional property. We recall that a Jordan derivation on a Banach algebra A is a linear mapping D : A → A such that D(a 2) = D(a)a + aD(a), ∀a ∈ A, or equivalently satisfying that D(a • b) = D (a) • b + a • D(b), ∀a, b ∈ A, (where, as ...
Maria Victoria Velasco +1 more
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A classical nonassociative operators topic is the continuity of Jordan derivations on Banach algebras which have some aditional property. We recall that a Jordan derivation on a Banach algebra A is a linear mapping D : A → A such that D(a 2) = D(a)a + aD(a), ∀a ∈ A, or equivalently satisfying that D(a • b) = D (a) • b + a • D(b), ∀a, b ∈ A, (where, as ...
Maria Victoria Velasco +1 more
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Jordan derivation of certain Jordan matrix algebras
Linear and Multilinear Algebra, 2008Let R be an arbitrary 2-torsionfree commutative ring, M(n, R) the matrix algebra consisting of all n × n matrices over R, S(n, R) (resp., D(n, R)) the subset of M(n, R) consisting of all symmetric (resp., diagonal) ones. In this article, we first determine all the Jordan subalgebras of S(n, R) containing D(n, R), then for any given Jordan subalgebra of
Dengyin Wang, Qian Hu, Chunguang Xia
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Jordan decomposable derivations
Communications in Algebra, 1988A derivation is called Jordan decomposable i-f it can be decomposed into a sum of commuting nil and semi-simple parts. In this paper, we study a subfamily of such derivations, the strongly decomposable derivations. After establishing some basic properties, we present an intrinsic criterion for such a derivation.
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Weak Jordan *-derivations of prime rings
Journal of Algebra and Its Applications, 2022Let * be an involution of a non-commutative prime ring [Formula: see text] with the maximal symmetric ring of quotients and the extended centroid of [Formula: see text] denoted by [Formula: see text] and [Formula: see text], respectively. Consider [Formula: see text] be an additive map, if [Formula: see text] for all [Formula: see text], then such a ...
Siddeeque, Mohammad Aslam +2 more
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Jordan Derivations of Reflexive Algebras
Integral Equations and Operator Theory, 2010Let \(\mathcal{A}\) be an algebra and \(\mathcal{M}\) be an \(\mathcal{A}\)-bimodule. A linear map \(\delta : \mathcal{A}\rightarrow \mathcal{M}\) is called a Jordan derivation (resp., a derivation) if \(\delta(A^2) = \delta(A)A + A\delta(A)\) for all \(A\in \mathcal{A}\) (resp., \(\delta(AB) = \delta(A)B + A\delta(B)\) for all \(A,B\in \mathcal{A}\)).
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