Results 341 to 350 of about 650,043 (363)
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1929
We have seen in Chapter VI, § 7 (p. 172), that logarithmic potentials are limiting forms of Newtonian potentials. We have seen also that harmonic functions in two dimensions, being special cases of harmonic functions in space, in that they are independent of one coordinate, partake of the properties of harmonic functions in space.
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We have seen in Chapter VI, § 7 (p. 172), that logarithmic potentials are limiting forms of Newtonian potentials. We have seen also that harmonic functions in two dimensions, being special cases of harmonic functions in space, in that they are independent of one coordinate, partake of the properties of harmonic functions in space.
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Logarithmic order and dual logarithmic order
2001We shall define the following four orders for strictly positive operators A and B on a Hilbert space H. Strictly logarithmic order (denoted by A≻ sl B) is defined by \(\frac{{A - I}}{{\log A}} > \frac{{B - I}}{{\log B}}\). Logarithmic order (denoted by A ≻ l B) is defined by \(\frac{{A - I}}{{\log A}} \geqslant \frac{{B - I}}{{\log B}}\). Strictly dual
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Recent progress on the elliptic curve discrete logarithm problem
Designs, Codes and Cryptography, 2015S. Galbraith, P. Gaudry
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Improving NFS for the Discrete Logarithm Problem in Non-prime Finite Fields
International Conference on the Theory and Application of Cryptographic Techniques, 2015R. Barbulescu+3 more
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Tables de Logarithmes de Logarithmes, Logarithmes de Cologarithmes, Logarithmes a Six Decimales.
Mathematics of Computation, 1966J. W. W., G. Barriere
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1986
We remember that we had trouble at the very beginning with the function 2 x (or 3 x , or 10 x ). It was intuitively very plausible that there should be such functions, satisfying the fundamental equation $$ 2^{x + y} = 2^x 2^y $$ for all numbers x, y, and 20 = 1, but we had difficulties in saying what we meant by \( 2^{\sqrt 2 } \) (or 2 π ).
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We remember that we had trouble at the very beginning with the function 2 x (or 3 x , or 10 x ). It was intuitively very plausible that there should be such functions, satisfying the fundamental equation $$ 2^{x + y} = 2^x 2^y $$ for all numbers x, y, and 20 = 1, but we had difficulties in saying what we meant by \( 2^{\sqrt 2 } \) (or 2 π ).
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Generic Hardness of the Multiple Discrete Logarithm Problem
International Conference on the Theory and Application of Cryptographic Techniques, 2015Aaram Yun
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Exponentially decreasing distributions for the logarithm of particle size
Proceedings of the Royal Society of London. A. Mathematical and Physical Sciences, 1977O. Barndorff-Nielsen
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