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Mersenne numbers as a difference of two Lucas numbers

Commentationes Mathematicae Universitatis Carolinae, 2023
Summary: Let \((L_n)_{n\geq 0}\) be the Lucas sequence. We show that the Diophantine equation \(L_n-L_m=M_k\) has only the nonnegative integer solutions \((n,m,k)=(2,0,1)\), \((3,1,2)\), \((3,2,1)\), \((4,3,2)\), \((5,3,3)\), \((6,2,4)\), \((6,5,3)\) where \(M_k=2^k-1\) is the \(k\)th Mersenne number and \(n>m\).
openaire   +3 more sources

Fibonacci and Lucas Numbers

1997
Consider the following number trick–try it out on your friends. You ask them to write down the numbers from 0 to 9. Against 0 and 1 they write any two numbers (we suggest two fairly small positive integers just to avoid tedious arithmetic, but all participants should write the same pair of numbers).
Peter Hilton   +2 more
openaire   +1 more source

Lucas-Sierpiński and Lucas-Riesel Numbers

The Fibonacci Quarterly, 2011
Daniel Baczkowski   +2 more
openaire   +1 more source

On Triangular Lucas Numbers

1991
In the paper [3], we have proved that the only triangular numbers (i.e., the positive integers of the form \( \frac{1}{2}m \)(m+1)) in the Fibonacci sequence $$ {u_n} + 2 = {u_{n + 1}} + {u_{{n^,}}}{u_0} = 0, {u_1} = 1 $$ are u ±1=u2=1, u4=3, u8=21 and u10=55. This verifies a conjecture of Vern Hoggatt [2].
openaire   +1 more source

Mersenne Numbers in Generalized Lucas Sequences

Proceedings of the Bulgarian Academy of Sciences
Let $$k \geq 2$$ be an integer and let $$(L_{n}^{(k)})_{n \geq 2-k}$$ be the $$k$$-generalized Lucas sequence with certain initial $$k$$ terms and each term afterward is the sum of the $$k$$ preceding terms. Mersenne numbers are the numbers of the form $$2^a-1$$, where $$a$$ is any positive integer.
ALAN, Murat, Altassan, Alaa
openaire   +2 more sources

Pseudoprimality related to the generalized Lucas sequences

Mathematics and Computers in Simulation, 2022
Ovidiu Bagdasar, Dorin Andrica
exaly  

On Some New Arithmetic Properties of the Generalized Lucas Sequences

Mediterranean Journal of Mathematics, 2021
Ovidiu Bagdasar   +2 more
exaly  

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