Results 71 to 80 of about 310,219 (199)
Flat local morphisms of rings with prescribed depth and dimension
Analele Stiintifice ale Universitatii Ovidius Constanta: Seria Matematica, 2016 For any pairs of integers (n,m) and (d, e) such that 0 ≤ n ≤ m, 0 ≤ d _ e, d ≤ n, e ≤ m and n -d ≤ m - e we construct a local flat ring morphism of noetherian local rings u : A → B such that dim(A) = n; depth(A) = d; dim(B) = m and depth(B) = e.
Ionescu Cristodor
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Infinity‐operadic foundations for embedding calculus
Journal of Topology, Volume 19, Issue 2, June 2026.Abstract Motivated by applications to spaces of embeddings and automorphisms of manifolds, we consider a tower of ∞$\infty$‐categories of truncated right modules over a unital ∞$\infty$‐operad O$\mathcal {O}$. We study monoidality and naturality properties of this tower, identify its layers, describe the difference between the towers as O$\mathcal {O}$
Manuel Krannich, Alexander Kupers
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On the finite generation of ideals in tensor triangular geometry
Bulletin of the London Mathematical Society, Volume 58, Issue 5, May 2026.Abstract Inspired by Cohen's characterization of Noetherian commutative rings, we study the finite generation of ideals in tensor triangular geometry. In particular, for an essentially small tensor triangulated category K$\mathcal {K}$ with weakly Noetherian spectrum, we show that every prime ideal in K$\mathcal {K}$ can be generated by finitely many ...
Tobias Barthel
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Rings Whose Pure-Projective Modules Have Maximal or Minimal Projectivity Domain
Journal of New TheoryIn this study, we investigate the projectivity domain of pure-projective modules. A pure-projective module is called special-pure-projective (s-pure-projective) module if its projectivity domain contains only regular modules. First, we describe all rings
Zübeyir Türkoğlu
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Linear Groups with Many Profinitely Closed Subgroups [PDF]
Advances in Group Theory and Applications, 2017 If G is a linear group with every subgroup of G of infinite Prüfer rank closed in the profinite topology on G, we prove that either every subgroup of G is closed in this topology or G itself has finite Prüfer rank.
B.A.F. Wehrfritz
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On hereditary rings and NoetherianV-rings [PDF]
Pacific Journal of Mathematics, 1982 The purpose of this paper is to examine conditions under which (1) a left noetherian left F-ring is left hereditary and (2) a left noetherian left F-ring is a two sided noetherian F-ring. For (1), left noetherian left F-rings which satisfy the restricted left minimum (RLM) condition are examined.
openaire +3 more sources
Measuring birational derived splinters
Bulletin of the London Mathematical Society, Volume 58, Issue 5, May 2026.Abstract This work is concerned with categorical methods for studying singularities. Our focus is on birational derived splinters, which is a notion that extends the definition of rational singularities beyond varieties over fields of characteristic zero. Particularly, we show that an invariant called ‘level’ in the associated derived category measures
Timothy De Deyn +3 more
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, 2002 Over the past 25 years, I have been immersed in research in Algebra and more particularly in ring theory. I embarked on writing this book on Smarandache rings (Srings) specially to motivate both ring theorists and Smarandache algebraists to develop and ...
Vasantha, Kandasamy
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A classification of Prüfer domains of integer‐valued polynomials on algebras
Bulletin of the London Mathematical Society, Volume 58, Issue 4, April 2026.Abstract Let D$D$ be an integrally closed domain with quotient field K$K$ and A$A$ a torsion‐free D$D$‐algebra that is finitely generated as a D$D$‐module and such that A∩K=D$A\cap K=D$. We give a complete classification of those D$D$ and A$A$ for which the ring IntK(A)={f∈K[X]∣f(A)⊆A}$\textnormal {Int}_K(A)=\lbrace f\in K[X] \mid f(A)\subseteq A ...
Giulio Peruginelli, Nicholas J. Werner
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Noetherian rings of composite generalized power series
Open MathematicsLet A⊆BA\subseteq B be an extension of commutative rings with identity, (S,≤)\left(S,\le ) a nonzero strictly ordered monoid, and S*=S\{0}{S}^{* }\left=S\backslash \left\{0\right\}.
Oh Dong Yeol
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