Results 71 to 80 of about 311,275 (193)
Power mean inequality of generalized trigonometric functions
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Bhayo, Barkat Ali, Vuorinen, Matti
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Determination of Bounds for the Jensen Gap and Its Applications
The Jensen inequality has been reported as one of the most consequential inequalities that has a lot of applications in diverse fields of science. For this reason, the Jensen inequality has become one of the most discussed developmental inequalities in ...
Hidayat Ullah +2 more
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Matrix power means and Pólya-Szegő type inequalities
Summary: It is shown that, if \(\mu\) is a compactly supported probability measure on \(\mathbb{M}^+_n\), then, for every unit vector \(\eta\in\mathbb{C}^n\), there exists at compactly supported probability measure (denoted by \(\langle\mu\eta,\eta\rangle)\) on \(\mathbb{R}^+\) so that the inequality \[\langle P_t(\mu)\eta,\eta\rangle\le P_t(\langle\mu
Mohsen Kian, Fatemeh Rashid
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Optimal inequalities between Seiffert's mean and power means [PDF]
For the Seiffert mean \(P(x,y):=(x-y)/[4\arctan (\sqrt{x/y})-\pi ]\), the author proves that the evaluation \(A_{p}\leq P\leq A_{q}\) holds if and only if ...
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Abstaract−In this paper, we introduce a new class of convex functions which is called (s, m)- preinvex functions in the second sense then we establish some new Hermite-Hadamard’s inequalities whose modulus of the first derivatives are in this novel ...
Badreddine Meftah
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A note on the proofs of generalized Radon inequality [PDF]
In this paper, we introduce and prove several generalizations of the Radon inequality. The proofs in the current paper unify and also are simpler than those in early published work.
Yongtao Li, Xian-Ming Gu, Xiao Jianci
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Sharp bounds by the power mean for the generalized Heronian mean
In this article, we answer the question: For p, ω ∈ ℝ with ω > 0 and p(ω - 2) ≠ 0, what are the greatest value r1 = r1(p, ω) and the least value r2 = r2(p, ω) such that the double inequality Mr1a,b 0 with a ≠ b?
Yong-Min Li, B. Long, Y. Chu
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Complementary inequalities to Davis-Choi-Jensen's inequality and operator power means
Let $f$ be an operator convex function on $(0,\infty)$, and $ $ be a unital positive linear maps on $B(H)$. we give a complementary inequality to Davis-Choi-Jensen's inequality as follows \begin{equation*} f( (A))\geq \frac{4R(A,B)}{(1+R(A,B))^2} (f(A)), \end{equation*} where $R(A, B)=\max\{r(A^{-1}B) ,r(B^{-1}A)\}$ and $r(A)$ is the spectral radius
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Fractional Ostrowski type inequalities for functions whose derivatives are s-preinvex
In this paper, we establish a new integral identity, and then we derive some new fractional Ostrowski type inequalities for functions whose derivatives are s-preinvex.
Badri Meftah, M. Merad, A. Souahi
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Some New Classes of Preinvex Functions and Inequalities
In this article, we introduce some new class of preinvex functions involving two arbitrary auxiliary functions. We derive some new integral inequalities for these classes of preinvex functions. We also discuss some special cases which can be deduced from
Muhammad Aslam Noor +2 more
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