Results 11 to 20 of about 21,622,505 (140)
On nonnil-S-Noetherian and nonnil-u-S-Noetherian rings
Analele Stiintifice ale Universitatii Ovidius Constanta: Seria MatematicaLet R be a commutative ring with identity, and let S be a multiplicative subset of R. Then R is called a nonnil-S-Noetherian ring if every nonnil ideal of R is S-finite.
Mahdou Najib +2 more
doaj +2 more sources
Generalization of the $S$-Noetherian concept [PDF]
, 2023 summary:Let $A$ be a commutative ring and ${\mathcal{S}}$ a multiplicative system of ideals. We say that $A$ is ${\mathcal{S}}$-Noetherian, if for each ideal $Q$ of $A$, there exist $I\in {\mathcal{S}}$ and a finitely generated ideal $F\subseteq Q$ such ...
Dabbabi, Abdelamir, Benhissi, Ali
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, 1970 The theory of near-rings has arisen in a variety of ways. There is a natural desire to generalise the theory of rings and skew fields by relaxing some of their defining axioms.
Holcombe, William Michael Lloyd
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On Semiprime Noetherian PI-Rings [PDF]
, 2000 Let R be a semiprime Noetherian PI-ring and Q(R) the semisimple Artinian ring of fractions of R. We shall prove the following conditions are equivalent: (1) the Krull dimention of R is at most one, (2) Any ring between R and Q(R) is again right ...
Chiba, Katsuo
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On right S-Noetherian rings and S-Noetherian modules [PDF]
, 2018 In this paper we study right S-Noetherian rings and modules, extending notions introduced by Anderson and Dumitrescu in commutative algebra to noncommutative rings.
TEKİR, ÜNSAL
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Projective prime ideals and localisation in pi-rings [PDF]
, 2001 The results here generalise [2, Proposition 4.3] and [9, Theorem 5.11]. We shall prove the following. THEOREM A. Let R be a Noetherian PI-ring. Let P be a non-idempotent prime ideal of R such that PR is projective. Then P is left localisable and RP is
Chatters, A. W. +5 more
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An extension of s-noetherian rings and modules [PDF]
, 2023 For any commutative ring $A$ we introduce a generalization of $S$-noetherian rings using a hereditary torsion theory $\sigma$ instead of a multiplicatively closed subset $S\subseteq{A}$. It is proved that totally noetherian w.r.t.
Jara Martínez, Pascual
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, 2007 summary:Let $R$ be a commutative ring and $S\subseteq R$ a given multiplicative set. Let $(M,\le )$ be a strictly ordered monoid satisfying the condition that $0\le m$ for every $m\in M$.
Liu, Zhongkui
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On modules satisfying s-noetherian spectrum condition
, 2022 Let R be a commutative ring having nonzero identity and M be a unital R-module. Assume that S ⊆ R is a multiplicatively closed subset of R. Then, M satisfies SNoetherian spectrum condition if for each submodule N of M, there exist s ∈ S and a finitely ...
TEKİR, ÜNSAL, KOÇ, SUAT
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, 2002 Over the past 25 years, I have been immersed in research in Algebra and more particularly in ring theory. I embarked on writing this book on Smarandache rings (Srings) specially to motivate both ring theorists and Smarandache algebraists to develop and ...
Vasantha, Kandasamy
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