Results 21 to 30 of about 5,518 (174)

On soluble groups whose subnormal subgroups are inert [PDF]

open access: yesInternational Journal of Group Theory, 2015
A subgroup H of a group G is called inert if‎, ‎for each g∈G ‎, ‎the index of H∩H g in H is finite‎. ‎We give a classification ‎of soluble-by-finite groups G in which subnormal subgroups are inert in the cases where G has no nontrivial torsion ...
Ulderico Dardano , Silvana Rinauro
doaj  

Locally finite p-groups with all subgroups either subnormal or nilpotent-by-Chernikov [PDF]

open access: yesInternational Journal of Group Theory, 2012
We pursue further our investigation, begun in [H.~Smith, Groups with all subgroups subnormal or nilpotent-by-{C}hernikov, emph{Rend. Sem. Mat. Univ. Padova} 126 (2011), 245--253] and continued in [G.~Cutolo and H.~Smith, Locally finite groups with all ...
H. Smith, G. Cutolo
doaj  

On σ-Residuals of Subgroups of Finite Soluble Groups

open access: yesMathematics, 2023
Let σ={σi:i∈I} be a partition of the set of all prime numbers. A subgroup H of a finite group G is said to be σ-subnormal in G if H can be joined to G by a chain of subgroups H=H0⊆H1⊆⋯⊆Hn=G where, for every j=1,⋯,n, Hj−1 is normal in Hj or Hj/CoreHj(Hj−1)
A. A. Heliel   +3 more
doaj   +1 more source

Frattini Argument for Hall subgroups

open access: yes, 2014
In the paper, it is proved that if a finite group $G$ possesses a $\pi$-Hall subgroup for a set $\pi$ of primes, then every normal subgroup $A$ of $G$ possesses a $\pi$-Hall subgroup $H$ such that ${G=AN_G(H)}$
Revin, Danila, Vdovin, Evgeny
core   +1 more source

On the Frattini subgroup of a finite group

open access: yes, 2016
We study the class of finite groups $G$ satisfying $\Phi (G/N)= \Phi(G)N/N$ for all normal subgroups $N$ of $G$. As a consequence of our main results we extend and amplify a theorem of Doerk concerning this class from the soluble universe to all finite ...
Aivazidis, Stefanos   +1 more
core   +1 more source

On numbers which are orders of nilpotent groups with bounded class [PDF]

open access: yesInternational Journal of Group Theory
Let $n$ be a positive integer. In this short note, we characterize those numbers $m$ for which any group of order $m$ is an $n$-Engel group and those numbers $m$ for which any group of order $m$ has all its subgroups subnormal of defect at most $n$.
Maria Ferrara
doaj   +1 more source

Sex-Related Differences in Risk Factors Associated With Nonhealing or Recurrence of Hyperthyroidism in Patients With Graves' Disease Treated With Radioactive Iodine. [PDF]

open access: yesHealth Care Sci
Age and thyroid volume were independent risk factors for the occurrence of nonhealing or recurrence of hyperthyroidism (NHRH) in female patients. Only free thyroxine (FT4) was independently associated with the occurrence of NHRH in male patients. ABSTRACT Background To evaluate sex‐related differences in the risk factors associated with nonhealing or ...
Shen H   +5 more
europepmc   +2 more sources

Existence criterion for Hall subgroups of finite groups

open access: yes, 2010
In the paper we obtain an existence criterion for Hall subgroups of finite groups in terms of a composition series.Comment: We made some editor corrections in the ...
Danila O. Revin   +2 more
core   +1 more source

A Survey of Subnormal Subgroups

open access: yesIrish Mathematical Society Bulletin, 1990
The author gives a survey (without proofs) of the high points of the theory of subnormal subgroups developed over the last fifty years. The article is intended as an introduction to the book by Lennox and Stonehewer.
openaire   +2 more sources

Groups with conjugacy classes of coprime sizes

open access: yesBulletin of the London Mathematical Society, Volume 58, Issue 3, March 2026.
Abstract Suppose that x$x$, y$y$ are elements of a finite group G$G$ lying in conjugacy classes of coprime sizes. We prove that ⟨xG⟩∩⟨yG⟩$\langle x^G \rangle \cap \langle y^G \rangle$ is an abelian normal subgroup of G$G$ and, as a consequence, that if x$x$ and y$y$ are π$\pi$‐regular elements for some set of primes π$\pi$, then xGyG$x^G y^G$ is a π ...
R. D. Camina   +8 more
wiley   +1 more source

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