Results 151 to 160 of about 10,663,991 (195)
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Refinements of some inequalities involving Berezin norms and Berezin number and related questions
ANNALI DELL'UNIVERSITA' DI FERRARA, 2023zbMATH Open Web Interface contents unavailable due to conflicting licenses.
M. Garayev, M. Guesba
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Estimates for the Berezin number inequalities
Journal of Pseudo-Differential Operators and ApplicationszbMATH Open Web Interface contents unavailable due to conflicting licenses.
M. Guesba, M. Garayev
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On Berezin Number Inequalities for Operator Matrices
Acta Mathematica Sinica, English Series, 2021For a bounded linear operator, acting in the reproducing kernel Hilbert space \(\mathcal{H}=\mathcal{H}(\Omega)\) over some set \(\Omega\), its Berezin symbol \(\tilde{A}\) is defined by \(\tilde{A}(\lambda)=\langle A\tilde{k}_\lambda, \tilde{k}_\lambda \rangle\), where \(\tilde{k}_\lambda\) the normalized reproducing kernel of \(\mathcal{H}\).
Sahoo, Satyajit +2 more
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Some new relations between the Berezin number and the Berezin norm of operators
Rocky Mountain Journal of Mathematics, 2022For a bounded linear operator \(A\) on a reproducing kernel Hilbert space with reproducing kernel \(K(z,w)\), the Berezin symbol, Berezin norm and Berezin number of \(A\) are defined, respectively, by \[ \tilde A(w):=\langle Ak_w,k_w\rangle, \quad \|A\|_{Ber} := \sup_w \|Ak_w\|, \quad \operatorname{ber}(A) :=\sup_w |\tilde A(w)|, \] where \(k_w(z):=K(z,
Çalisir, Irem +2 more
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IMPROVING BOUNDS FOR GENERALIZED BEREZIN NUMBER OF OPERATORS
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Berezin number inequalities of operators on reproducing kernel Hilbert spaces
Rocky Mountain Journal of Mathematics, 2022Several new upper bounds for the Berezin number of bounded linear operators defined on reproducing kernel Hilbert spaces are given. The bounds obtained here improve on the earlier ones.
Pintu Bhunia, K. Paul
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Inequalities involving Berezin norm and Berezin number of Hilbert space operators
Summary: This paper presents several Berezin number and norm inequalities for Hilbert space operators. These inequalities improve some earlier related inequalities. Among other inequalities, it is shown that if \(A\) is a bounded linear operator on a Hilbert space, then \[ \mathbf{ber}^2(A) \leqslant \left\|\frac{A^\ast A + AA^\ast}{2} - \frac{1}{2R ...
Elham Nikzat, M. Omidvar
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Complex Analysis and Operator Theory
In this note, we introduce a novel norm, termed the t-\documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength ...
R. Nayak, Pintu Bhunia
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In this note, we introduce a novel norm, termed the t-\documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength ...
R. Nayak, Pintu Bhunia
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Inequalities related to Berezin norm and Berezin number of operators
2022Summary: The Berezin symbol \(\widetilde{A}\) of an operator \(A\) on the reproducing kernel Hilbert space \(\mathcal{H}(\Omega)\) over some set \(\Omega\) with the reproducing kernel \(k_\lambda\) is defined by \[ \widetilde{A}(\lambda) = \left\langle A \widehat{k}_\lambda,\widehat{k}_\lambda \right\rangle,\; \lambda \in \Omega.
Basaran, Hamdullah +2 more
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Further refinements of the Berezin number inequalities on operators
Linear and multilinear algebra, 2021In this paper, we obtain some inequalities for the Berezin number of operators on reproducing kernel Hilbert spaces by using the Krein–Lin inequality and refinements of the Young inequality.
U. Yamancı, İsmail Murat Karlı
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