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The fitness landscape of a form II rubisco in a photosynthetic bacterium guides engineering of oxygen tolerance. [PDF]
Hoffmann UA +14 more
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Digital infrastructure to support and share daily high-throughput experimental materials research.
Mittmann LA +11 more
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Assistive algorithms influence neural representations in motor brain-computer interfaces. [PDF]
Rajeswaran P +3 more
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A Combinatorial Identity and the World Series
SIAM Review, 1993In this note the author gives a simple probabilistic proof of a combinatorial identity by calculating the winning probability in the World Series. The winning probabilities and the expected length of the championship series are given by the applications of the identity and its generalization.
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A Family of Combinatorial Identities
Canadian Mathematical Bulletin, 1972In a recent paper, Murray Eden [5] generalized the simple identity for the Eulerian product,1.1and obtained the following infinite family of identities:For A= 1,2, 3,…, let1.2where we assume throughout that |x| < 1, empty products equal unity and empty sums equal zero; then1.3As Eden noted, Fh(b;x) is the generating function of ph(m, n) which ...
Andrews, G. E. +2 more
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COMBINATORIAL IDENTITIES AND HYPERGEOMETRIC FUNCTIONS
Rocky Mountain Journal of Mathematics, 2022zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Alzer, Horst, Richards, Kendall C.
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On two combinatorial identities
Journal of Computational Methods in Sciences and Engineering, 2017Two combinatorial identities are proved. The first one allows easy to establish connections between Bernoulli and Stirling numbers and values of zeta function of integer arguments and to find numerous identities, including the new ones, for these quantities.
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Publicationes Mathematicae Debrecen, 2022
The author proves that the only solution of the difference equation \[ \Phi (2(v+1))+\sum^{v}_{k=1}\binom{2v}{2k-1} \Phi (2k) \Phi (2(v-k+1))=0 \] subject to the initial condition \(\Phi (2)=1/4\) is \(\Phi (2k)=((2^{2k}-1)/2k) B_{2k}\) where the \(B_{2k}\) are the even-indexed Bernoulli numbers. Using this result, he then proves that (1/k)\(| B_{2k}|^{
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The author proves that the only solution of the difference equation \[ \Phi (2(v+1))+\sum^{v}_{k=1}\binom{2v}{2k-1} \Phi (2k) \Phi (2(v-k+1))=0 \] subject to the initial condition \(\Phi (2)=1/4\) is \(\Phi (2k)=((2^{2k}-1)/2k) B_{2k}\) where the \(B_{2k}\) are the even-indexed Bernoulli numbers. Using this result, he then proves that (1/k)\(| B_{2k}|^{
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