Results 1 to 10 of about 704,075 (198)
A Quasi-Commutative Ring That is Not Neo-Commutative [PDF]
Proceedings of the American Mathematical Society, 1994 An example of a ring that is quasi-commutative but not neo-commutative is given.
Irving Kaplansky
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Regular divisor graph of finite commutative ring
Tikrit Journal of Pure Science, 2023 Let R be a finite commutative ring with identity 1. We introduce a new graph called regular divisor graph and denoted by . We classify the finite commutative ring to get a special graph and we are going to study some properties of this graph, clique ...
Payman Abbas Rashid, Hataw Saleem Rashid
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Bulletin of the Australian Mathematical Society, 2006 A ring is called a commutator ring if every element is a sum of additive commutators. In this note we give examples of such rings. In particular, we show that given any ring R, a right R-module N, and a nonempty set Ω, EndR(⌖ΩN) and EndR(ΠΩN) are commutator rings if and only if either Ω is infinite or EndR(N) is itself a commutator ring.
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COMMUTATIVITY THEOREMS FOR RINGS WITH CONSTRAINTS ON COMMUTATORS
Tamkang Journal of Mathematics, 1995 Let $R$ be a left (resp. right) $s$-unital ring and $m$ be a positive integer. Suppose that for each $y$ in $R$ there exist $J(t)$, $g(t)$, $h(t)$ in $Z[t]$ such that $x^m[x,y]= g(y)[x,y^2f(y)]h(y)$ (resp. $[x,y]x^m= g(y)[x,y^2f(y)]h(y))$ for all $x$ in $R$. Then $R$ is commutative (and conversely).
Abujabal, H. A. S., Ashraf, Mohd.
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On the Genus of the Idempotent Graph of a Finite Commutative Ring
Discussiones Mathematicae - General Algebra and Applications, 2021 Let R be a finite commutative ring with identity. The idempotent graph of R is the simple undirected graph I(R) with vertex set, the set of all nontrivial idempotents of R and two distinct vertices x and y are adjacent if and only if xy = 0.
Belsi G. Gold, Kavitha S., Selvakumar K.
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Polynomial Rings over Pseudovaluation Rings
International Journal of Mathematics and Mathematical Sciences, 2007 Let R be a ring. Let σ be an automorphism of R. We define a σ-divided ring and prove the following. (1) Let R be a commutative pseudovaluation ring such that x∉P for any P∈Spec(R[x,σ]) . Then R[x,σ] is also a pseudovaluation ring.
V. K. Bhat
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Generalized Commutative Rings [PDF]
Nagoya Mathematical Journal, 1966 Among his various interests in algebra Nakayama also took part in the various researches, published in the early and middle 1950’s, which dealt with the commutativity of rings. This paper, which studies a problem of a related sort, thus seems appropriate in a Journal honoring his memory.We shall study a certain class of rings which satisfy a weak form ...
Belluce, L. P. +2 more
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Characterization of fuzzy neighborhood commutative division rings II
International Journal of Mathematics and Mathematical Sciences, 1995 In [4] we produced a characterization of fuzzy neighborhood commutative division rings; here we present another characterization of it in a sense that we minimize the conditions so that a fuzzy neighborhood system is compatible with the commutative ...
T. M. G. Ahsanullah, Fawzi A. Al-Thukair
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Elementary reduction of matrices over Bezout ring with stable range 1 (in Ukrainian) [PDF]
Математичні Студії, 2012 We prove that a commutative Bezout ring with stable range 1 is a ring with elementary reduction of matrices and that every singular matrice over commutative Bezout ring with stable range 1 is products of idempotent matrices.
O. M. Romaniv
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Generalized periodic and generalized Boolean rings
International Journal of Mathematics and Mathematical Sciences, 2001 We prove that a generalized periodic, as well as a generalized Boolean, ring is either commutative or periodic. We also prove that a generalized Boolean ring with central idempotents must be nil or commutative. We further consider conditions which imply
Howard E. Bell, Adil Yaqub
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