Results 11 to 20 of about 2,551 (252)

Bounds on the global double Roman domination number in graphs

open access: yesDiscussiones Mathematicae Graph Theory, 2022
Summary: Let \(G\) be a simple graph of order \(n\) and let \(\gamma_{\mathrm{gdR}}(G)\) be the global double Roman domination number of \(G\). In this paper, we give some upper bounds on the global double Roman domination number of \(G\). In particular, we completely characterize the graph \(G\) with \(\gamma_{\mathrm{gdR}}(G)=2n-2\) and \(\gamma_ ...
Guoliang Hao   +3 more
semanticscholar   +5 more sources

Double Roman domination number

open access: yesDiscrete Applied Mathematics, 2018
zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Aparna Lakshmanan S
exaly   +6 more sources

The Double Roman Domination Numbers of Generalized Petersen Graphs P(n, 2) [PDF]

open access: yesMathematics, 2018
A double Roman dominating function (DRDF) f on a given graph G is a mapping from V ( G ) to { 0 , 1 , 2 , 3 } in such a way that a vertex u for which f ( u ) = 0 has at least a neighbor labeled 3 or two neighbors both labeled 2 and a vertex u for which f ( u ) = 1 has at least a neighbor labeled 2 or 3.
Huiqin Jiang, Pu Wu, Zehui Shao
exaly   +7 more sources

More results on the signed double Roman domination number of graphs

open access: yesAKCE International Journal of Graphs and Combinatorics
Published by Dep.
Sheikholeslami, Seyed Mahmoud   +1 more
semanticscholar   +6 more sources

Bounds on the total double Roman domination number of graphs

open access: yesDiscussiones Mathematicae Graph Theory, 2023
Summary: Let \(G\) be a simple graph with no isolated vertex and let \(\gamma_{tdR}(G)\) be the total double Roman domination number of \(G\). In this paper, we present lower and upper bounds on \(\gamma_{tdR}(G)\) of a graph \(G\) in terms of the order, open packing number and the numbers of support vertices and leaves, and we characterize all ...
Guoliang Hao   +3 more
semanticscholar   +3 more sources

Double Roman domination and domatic numbers of graphs [PDF]

open access: yesCommunications in Combinatorics and Optimization, 2018
Summary: A double Roman dominating function on a graph \(G\) with vertex set \(V(G)\) is defined in [\textit{R. A. Beeler} et al., Discrete Appl. Math. 211, 23--29 (2016; Zbl 1348.05146)] as a function \(f:V(G)\rightarrow\{0,1,2,3\}\) having the property that if \(f(v)=0\), then the vertex \(v\) must have at least two neighbors assigned 2 under \(f ...
L. Volkmann
doaj   +4 more sources

An improved upper bound on the independent double Roman domination number of trees

open access: yesAKCE International Journal of Graphs and Combinatorics, 2022
AbstractFor a graph [Formula: see text] an independent double Roman dominating function (IDRDF) is a function [Formula: see text] having the property that: (i) every vertex [Formula: see text] with f(v) = 0 has a neighbor u with f(u) = 3 or at least two neighbors x and y such that [Formula: see text] (ii) every vertex [Formula: see text] with f(v) = 1 ...
F. Nahani Pour   +3 more
semanticscholar   +4 more sources

Some Progress on the Double Roman Domination in Graphs

open access: yesDiscussiones Mathematicae Graph Theory, 2019
For a graph G = (V,E), a double Roman dominating function (or just DRDF) is a function f : V → {0, 1, 2, 3} having the property that if f(v) = 0 for a vertex v, then v has at least two neighbors assigned 2 under f or one neighbor assigned 3 under f, and ...
N. J. Rad, Hadi Rahbani
semanticscholar   +4 more sources

On the Outer Independent Double Roman Domination Number [PDF]

open access: yesBulletin of the Iranian Mathematical Society, 2021
zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Doost Ali Mojdeh   +3 more
semanticscholar   +5 more sources

Double Roman domination

open access: yesDiscrete Applied Mathematics, 2016
For a graph G=(V,E), a double Roman dominating function is a function f:V→{0,1,2,3} having the property that if f(v)=0, then vertex v must have at least two neighbors assigned 2 under f or one neighbor with f(w)=3, and if f(v)=1, then vertex v must have ...
TERESA W Haynes, Stephen T Hedetniemi
exaly   +3 more sources

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