Results 121 to 130 of about 3,245 (221)

A survey of s-unital and locally unital rings

open access: yesRevista Integración, 2019
We gather some classical results and examples that show strict inclusion between the families of unital rings, rings with enough idempotents, rings with sets of local units, locally unital rings, s-unital rings and idempotent rings.
Patrik Nystedt
doaj  

Minimal idempotency, partial idempotency, search heuristics and constructive algorithms for idempotent integers

open access: yesPublications mathématiques de Besançon. Algèbre et théorie des nombres
Previous work established the set of square-free integers n with at least one factorization n = p
openaire   +1 more source

Idempotents in symmetric semigroups

open access: yesJournal of Combinatorial Theory, Series A, 1972
AbstractWe count the number of idempotent elements in a certain section of the s symmetric semigroup Sn on n letters. As a corollary of our result we have that every maximal principal right ideal of Sn contains ∑i=1n−1in−i−1(n−2i−1)+(n−1i) idempotent elements.
openaire   +3 more sources

Categorical idempotents via shifted 0-affine algebras

open access: yes, 2023
We show that a categorical action of shifted 0-affine algebra naturally gives two families of pairs of complementary idempotents in the triangulated monoidal category of triangulated endofunctors for each weight category.
Hsu, You-Hung
core  

Varieties of idempotents in nonassociative algebras

open access: yes, 2019
In this paper, we study the variety of all nonassociative (NA) algebras from the idempotent point of view. We are interested, in particular, in the spectral properties of idempotents when algebra is generic, i.e. idempotents are in general position.
Krasnov, Yakov,, Tkachev, Vladimir,
core   +1 more source

The boundary algebra of a GL m -dimer. [PDF]

open access: yesCommun Algebra, 2020
Andritsch L.
europepmc   +1 more source

Semirings generated by idempotents

open access: yes
We prove that a semiring multiplicatively generated by its idempotents is commutative and Boolean, if every idempotent in the semiring has an orthogonal complement. We prove that a semiring additively generated by its idempotents is commutative, if every
Dolžan, David
core  

Grassmannians and Cluster Structures. [PDF]

open access: yesBull Iran Math Soc, 2021
Baur K.
europepmc   +1 more source

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