Results 31 to 40 of about 776,655 (324)

On the Total Double Roman Domination [PDF]

open access: yesIEEE Access, 2019
Let G = (V, E) be a simple graph. A double Roman dominating function (DRDF) on G is a function f from the vertex set V of G into {0, 1, 2, 3} such that if f (u) = 0, then u must have at least two neighbors assigned 2 or one neighbor assigned 3 under f ...
Zehui Shao   +3 more
doaj   +3 more sources

Strong Equality Between the Roman Domination and Independent Roman Domination Numbers in Trees

open access: yesDiscussiones Mathematicae Graph Theory, 2013
A Roman dominating function (RDF) on a graph G = (V,E) is a function f : V −→ {0, 1, 2} satisfying the condition that every vertex u for which f(u) = 0 is adjacent to at least one vertex v for which f(v) = 2.
Chellali Mustapha, Rad Nader Jafari
doaj   +3 more sources

More results on the signed double Roman domination number of graphs

open access: goldAKCE International Journal of Graphs and Combinatorics
A signed double Roman dominating function (SDRD-function) on a graph G is defined as a function [Formula: see text] having the property that [Formula: see text] for each [Formula: see text] and if [Formula: see text], then the vertex u must have a ...
Seyed Mahmoud Sheikholeslami   +1 more
doaj   +2 more sources

Integer Linear Programming Formulations for Triple and Quadruple Roman Domination Problems [PDF]

open access: greenarXiv.org, 2023
Roman domination is a well researched topic in graph theory. Recently two new variants of Roman domination, namely triple Roman domination and quadruple Roman domination problems have been introduced, to provide better defense strategies. However, triple
Sanath Kumar Vengaldas   +3 more
openalex   +3 more sources

Some Results on the Strong Roman Domination Number of Graphs [PDF]

open access: yesMathematics Interdisciplinary Research, 2020
Let G=(V,E) be a finite and simple graph of order n and maximum‎ ‎degree Δ(G)‎. ‎A strong Roman dominating function on a‎ ‎graph  G  is a function  f‎:V (G)→{0‎, ‎1,… ,‎[Δ(G)/2 ]‎+ ‎1}  satisfying the condition that every‎ ‎vertex v for which  f(v)=0  is
Akram Mahmoodi   +2 more
doaj   +1 more source

Perfect Domination, Roman Domination and Perfect Roman Domination in Lexicographic Product Graphs

open access: yesFundamenta Informaticae, 2022
The aim of this paper is to obtain closed formulas for the perfect domination number, the Roman domination number and the perfect Roman domination number of lexicographic product graphs. We show that these formulas can be obtained relatively easily for the case of the first two parameters.
Martinez, A. Cabrera   +2 more
openaire   +3 more sources

Total double Roman domination in graphs [PDF]

open access: yesCommunications in Combinatorics and Optimization, 2020
Let $G$ be a simple graph with vertex set $V$. A double Roman dominating function (DRDF) on $G$ is a function $f:V\rightarrow\{0,1,2,3\}$ satisfying that if $f(v)=0$, then the vertex $v$ must be adjacent to at least two vertices assigned $2$ or one ...
Guoliang Hao   +2 more
doaj   +1 more source

On the Quasi-Total Roman Domination Number of Graphs

open access: yesMathematics, 2021
Domination theory is a well-established topic in graph theory, as well as one of the most active research areas. Interest in this area is partly explained by its diversity of applications to real-world problems, such as facility location problems ...
Abel Cabrera Martínez   +2 more
doaj   +1 more source

Algorithmic Results for Weak Roman Domination Problem in Graphs [PDF]

open access: greenDiscrete Applied Mathematics
Consider a graph $G = (V, E)$ and a function $f: V \rightarrow \{0, 1, 2\}$. A vertex $u$ with $f(u)=0$ is defined as \emph{undefended} by $f$ if it lacks adjacency to any vertex with a positive $f$-value.
Kaustav Paul, Ankit Sharma, Arti Pandey
openalex   +2 more sources

A note on the bounds of Roman domination numbers

open access: yesAIMS Mathematics, 2021
Let $G$ be a graph and $f: V(G) \rightarrow \{0,1,2\}$ be a mapping. $f$ is said to be a Roman dominating function of $G$ if every vertex $u$ for which $f(u) = 0$ is adjacent to at least one vertex $v$ for which $f(v)=2$.
Zepeng Li
doaj   +1 more source

Home - About - Disclaimer - Privacy