Results 181 to 190 of about 649 (235)

Energetic Offset in Organic Solar Cells‐ Importance, Confusion and Outlook

open access: yesAdvanced Materials, EarlyView.
Energetic offsets in organic solar cells (OSCs) remain a subject of debate due to measurement‐ and lab‐dependent discrepancies. This Perspective clarifies the physical origins of these variations and identifies temperature‐dependent electro‐optical methods as a reliable approach to obtain consistent offset values.
Nakul Jain   +5 more
wiley   +1 more source

Ricci Curvature Tensor-Based Volumetric Segmentation. [PDF]

open access: yesInt J Comput Vis
Huang J, Chen K, Alpers A, Lei N.
europepmc   +1 more source

Advances on strictly Δ -modular IPs. [PDF]

open access: yesMath Program
Nägele M   +3 more
europepmc   +1 more source

Unveiling patterns: an exploration of machine learning techniques for unsupervised feature selection in single-cell data. [PDF]

open access: yesBrief Bioinform
Chatterjee N   +6 more
europepmc   +1 more source

RNAprecis: Prediction of full-detail RNA conformation from the experimentally best-observed sparse parameters. [PDF]

open access: yesPLoS Comput Biol
Wiechers H   +9 more
europepmc   +1 more source

Spherically symmetric teleparallel geometries. [PDF]

open access: yesEur Phys J C Part Fields
Coley AA   +3 more
europepmc   +1 more source

On the Surjectivity of the Exponential Function of Solvable Lie Groups

Mathematische Nachrichten, 1998
AbstractFor a solvable Lie group G the surjectivity of the exponential function expG is equivalent to the connectedness of the near‐Cartan subgroups and to the connectedness of the centralizers in a Cartan subgroup of all nilpotent elements in its Lie algebra g.
exaly   +2 more sources

Lie Solvable Group Rings

Canadian Journal of Mathematics, 1973
Let K[G] denote the group ring of G over the field K. One of the interesting problems which arises in the study of such rings is to find precisely when they satisfy polynomial identities. This has been solved for char K = 0 in [1] and for char K = p > 0 in [3]. The answer is as follows.
Passi, I. B. S.   +2 more
openaire   +2 more sources

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