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Trees with Double Roman Domination Number Twice the Domination Number Plus Two

Iranian Journal of Science and Technology, Transaction A: Science, 2018
A double Roman dominating function (DRDF) on a graph $$G=(V,E)$$ is a function $$f:V(G)\rightarrow \{0,1,2,3\}$$
Mustapha Chellali   +2 more
exaly   +2 more sources

Double Roman Domination: A Survey

open access: yesMathematics, 2023
Since 2016, when the first paper of the double Roman domination appeared, the topic has received considerable attention in the literature. We survey known results on double Roman domination and some variations of the double Roman domination, and a list ...
Janez Žerovnik, Darja Rupnik Poklukar
exaly   +2 more sources

Double Roman domination

open access: yesDiscrete Applied Mathematics, 2016
For a graph G=(V,E), a double Roman dominating function is a function f:V→{0,1,2,3} having the property that if f(v)=0, then vertex v must have at least two neighbors assigned 2 under f or one neighbor with f(w)=3, and if f(v)=1, then vertex v must have ...
Teresa Haynes, Stephen T Hedetniemi
exaly   +2 more sources

Total double Roman domination numbers in digraphs

Discrete Mathematics, Algorithms and Applications, 2021
Let [Formula: see text] be a finite and simple digraph with vertex set [Formula: see text]. A double Roman dominating function (DRDF) on digraph [Formula: see text] is a function [Formula: see text] such that every vertex with label 0 has an in-neighbor with label 3 or two in-neighbors with label 2 and every vertex with label 1 have at least one in ...
Jafar Amjadi, F. Pourhosseini
openaire   +2 more sources

DOUBLE ROMAN DOMINATION NUMBER OF MIDDLE GRAPH

South East Asian J. of Mathematics and Mathematical Sciences, 2022
For any graph G(V,  E), a function f : V (G)    0, 1, 2, 3     is called Double Roman dominating function (DRDF) if the following properties holds, If f (v) = 0, then there exist two vertices v1, v2 ∈ N (v) for which f (v1) = f (v2) = 2 or there exist one vertex u ∈ N (v) for which f (u) = 3.∈ If f (v) = 1, then there exist one vertex u N (v) for which
Shirkol, Shailaja S.   +2 more
openaire   +2 more sources

Signed double Roman domination numbers in digraphs

Annals of the University of Craiova - Mathematics and Computer Science Series, 2021
"Let $D=(V,A)$ be a finite simple digraph. A signed double Roman dominating function (SDRD-function) on the digraph $D$ is a function $f:V(D)\rightarrow\{-1,1,2, 3\}$ satisfying the following conditions: (i) $\sum_{x\in N^-[v]}f(x)\ge 1$ for each $v\in V(D)$, where $N^-[v]$ consist of $v$ and all in-neighbors of $v$, and (ii) if $f(v)=-1$, then the ...
Jafar Amjadi, Fatemeh Pourhosseini
openaire   +1 more source

An Upper Bound on the Double Roman Domination Number

Bulletin of the Iranian Mathematical Society, 2020
zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Ouldrabah, Lyes, Volkmann, Lutz
openaire   +1 more source

Double Roman domination subdivision number in graphs

Asian-European Journal of Mathematics, 2021
For a graph [Formula: see text], a double Roman dominating function is a function [Formula: see text] having the property that if [Formula: see text], then vertex [Formula: see text] must have at least two neighbors assigned [Formula: see text] under [Formula: see text] or one neighbor with [Formula: see text], and if [Formula: see text], then vertex [
Amjadi, J., Sadeghi, H.
openaire   +2 more sources

Twin signed double Roman domination numbers in directed graphs

Discrete Mathematics, Algorithms and Applications, 2022
Let [Formula: see text] be a finite simple directed graph (shortly digraph). A function [Formula: see text] is called a twin signed double Roman dominating function (TSDRDF) if (i) every vertex [Formula: see text] with [Formula: see text] has at least two in-neighbor assigned a 2 or at least an in-neighbor [Formula: see text] with [Formula: see text],
Akram Mahmoodi   +2 more
openaire   +2 more sources

Roman Domination and Double Roman Domination Numbers of Sierpiński Graphs $$S(K_n,t)$$

Bulletin of the Malaysian Mathematical Sciences Society, 2021
Sierpiński graph \(S_n^t\) can be defined recursively as \(S_n^1\cong K_n\) and one obtains \(S_n^{t+1}\) from \(S_n^t\) by replacing each vertex from \(S_n^t\) by a copy of \(K_n\) and adding some special edges between these copies of \(K_n\). Let \(G\) be a graph.
openaire   +2 more sources

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