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Melting of Io by Tidal Dissipation
Science, 1979The dissipation of tidal energy in Jupiter's satellite Io is likely to have melted a major fraction of the mass. Consequences of a largely molten interior may be evident in pictures of Io's surface returned by Voyager I.
P Cassen, S J Peale
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Explicitly Modelled Deep-Time Tidal Dissipation and Its Implication for Lunar History [PDF]
Earth and Planetary Science Letters, 2017 Dissipation of tidal energy causes the Moon to recede from the Earth. The currently measured rate of recession implies that the age of the Lunar orbit is 1500 My old, but the Moon is known to be 4500 My old.
Matthew T. Huber, Jonathan Buzan
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Journal of Geophysical Research: Solid Earth, 1981
Euler's equations of motion, modified to include elasticity and solid friction, were used to study the rotation of the moon. Two heuristic models for the anelasticity were considered: Q independent of frequency and Q inversely proportional to the frequency of the strain oscillation. Parameters in each model were estimated by weighted least squares from
R. J. Cappallo +3 more
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Euler's equations of motion, modified to include elasticity and solid friction, were used to study the rotation of the moon. Two heuristic models for the anelasticity were considered: Q independent of frequency and Q inversely proportional to the frequency of the strain oscillation. Parameters in each model were estimated by weighted least squares from
R. J. Cappallo +3 more
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New Constraints on Io's and Jupiter's Tidal Dissipation
Icarus, 2005 International audienceAlthough the quest for tidal accelerations among the Galilean satellites has been ongoing since the beginning of the last century, no real agreement has been found so far.
Gabriel Tobie
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Tidal disruption of dissipative planetesimals
Icarus, 1985A self-consistent numerical model is developed for the tidal disruption of a solid planetesimal. The planetesimal is treated as a highly viscous, slightly compressible fluid whose disturbed parts are an inviscid, pressureless fluid undergoing distortion and disruption. The distortions were constrained to being symmetrical above and below the equatorial
H. Mizuno, A.P. Boss
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Journal of Geophysical Research, 1963
Dissipation of tidal energy in the moon was calculated under the assumption that it can be represented as due to imperfect elasticity. If the factor 1/Q for dissipation per cycle is assumed to be 1/100 for distortional strain energy and 1/1000 for dilatational strain energy, the heat now being generated in the moon by tides is less than 0.010 erg/g/yr.;
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Dissipation of tidal energy in the moon was calculated under the assumption that it can be represented as due to imperfect elasticity. If the factor 1/Q for dissipation per cycle is assumed to be 1/100 for distortional strain energy and 1/1000 for dilatational strain energy, the heat now being generated in the moon by tides is less than 0.010 erg/g/yr.;
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Tidal dissipation in the earth and planets
Physics of the Earth and Planetary Interiors, 1968The discrepancy between seismic and tidal effective Q values can be attributed to dissipation in the shallow seas. At the present time there is no need to invoke frequency or amplitude dependence. Present data does not allow an accurate determination for dissipation in the Earth's interior from tidal or astronomical data but bounds can be placed on ...
Lagus, Peter L., Anderson, Don L.
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Tidal dissipation in a viscoelastic planet
Journal of Geophysical Research: Solid Earth, 1986The rates of energy dissipation in tidally distorted Kelvin‐Voigt, Maxwell, and standard linear solid (SLS) viscoelastic moon models are calculated for a hypothetical past lunar orbit with semimajor axis 34.2 earth radii and obliquity = 49°. Viscosities of 1014 and 1018 Pa s for the Kelvin‐Voigt and Maxwell rheologies, respectively, are needed to match
Martin Ross, Gerald Schubert
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Nature, 1923
IF g denote the intensity of surface gravity, the density of water, and h the elevation of the water surface above its mean position, the potential energy of the oceanic tide is ½g h2 per unit area. The kinetic energy must be comparable. If h has the equilibrium amplitude of 35 cm., the total energy of the ocean, the area of which is 3·7 × 1018 cm.2 ...
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IF g denote the intensity of surface gravity, the density of water, and h the elevation of the water surface above its mean position, the potential energy of the oceanic tide is ½g h2 per unit area. The kinetic energy must be comparable. If h has the equilibrium amplitude of 35 cm., the total energy of the ocean, the area of which is 3·7 × 1018 cm.2 ...
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Tidal Dissipation in the Oceans
1978The energy balance per unit of sea floor is $$ \frac{d}{{dt}}\left( {KE} \right) + \frac{d}{{dt}}\left( {PE} \right) + \frac{d}{{dt}} \cdot {\nabla _s}\left( {energyflux} \right) = \frac{{dW}}{{dt}} + \frac{{dE}}{{dt}} $$ (1) KE is the kinetic energy of the tidal currents, PE the potential energy, both per unit of surface.
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