Results 11 to 20 of about 127 (112)

Distribution of genus numbers of abelian number fields

open access: yesJournal of the London Mathematical Society, Volume 107, Issue 6, Page 2197-2217, June 2023., 2023
Abstract We study the quantitative behaviour of genus numbers of abelian extensions of number fields with given Galois group. We prove an asymptotic formula for the average value of the genus number and show that any given genus number appears only 0%$0\%$ of the time.
Christopher Frei   +2 more
wiley   +1 more source

Complete form of Furuta inequality [PDF]

open access: yesProceedings of the American Mathematical Society, 2008
The authors give a Furuta type order preserving operator inequality (they call it \textit{complete form of the Furuta inequality}) as follows: Let \(A\) and \(B\) be bounded linear operators on a complex Hilbert space with \(A\geq B\geq 0\) and let \(r\geq 0\), \(p>p_{0}>0\) and \(s=\min\{p, 2p_{0}+\min\{1,r\}\}\).
Yuan, Jiangtao, Gao, Zongsheng
openaire   +2 more sources

Complements to the Furuta inequality

open access: yesProceedings of the Japan Academy, Series A, Mathematical Sciences, 1994
zbMATH Open Web Interface contents unavailable due to conflicting licenses.
Fujii, Masatoshi   +2 more
openaire   +2 more sources

Around the Furuta inequality the operator inequalities [PDF]

open access: yesInternational Journal of Mathematics and Mathematical Sciences, 1993
For positive operators A and B with A invertible it is shown that implies . The inequalities in the title for 0 ≤ B ≤ A are then derived as a conquence.
openaire   +1 more source

Further extension of Furuta inequality [PDF]

open access: yesJournal of Mathematical Inequalities, 2010
If A2n A2n−1 ··· A2 A1 B 0, with A1 > 0,t1,t2,···,tn−1, tn ∈ (0,1) and p1,p2,···,p2n−1,p2n 1 for a natural number n. Then the following inequality holds for r tn A2n 1−t n+r {A2n r 2 (A2n−1 −tn 2 {A2(n−1) tn−1 2 ···A4 t2 2 (A3 −t2 2 {A2 t1 2 (A1 −t1 2 B p1A1 −t1 2 ) p2 A2 t1 2 } p3A3 −t2 2 ) p4A4 t2 2 ···A2(n−1) tn−1 2 } p2n−1A2n−1 ...
Changsen Yang, Yaqing Wang
openaire   +1 more source

The best possibility of the grand Furuta inequality [PDF]

open access: yesProceedings of the American Mathematical Society, 1999
Let A , B ∈
openaire   +3 more sources

On a reverse Heinz–Kato–Furuta inequality

open access: yesLinear Algebra and its Applications, 2012
In a Minkowski inner product space \((M, [\cdot,\cdot]_J)\), for timelike \(x\) and arbitary \(y\), we have the reverse Schwarz inequality: \[ |[x,y]_J|^2\geq [x,x]_J [y,y]_J. \] In this paper, the authors generalize it to several types of inequalities. The first two are Theorem 3.1 (reverse determinant Hadamard theorem).
Bebiano, N.   +2 more
openaire   +1 more source

Some Properties of Furuta Type Inequalities and Applications [PDF]

open access: yesAbstract and Applied Analysis, 2014
This work is to consider Furuta type inequalities and their applications. Firstly, some Furuta type inequalities underA≥B≥0are obtained via Loewner-Heinz inequality; as an application, a proof of Furuta inequality is given without using the invertibility of operators.
Jiangtao Yuan, Caihong Wang
openaire   +4 more sources

Best possibility of the Furuta inequality [PDF]

open access: yesProceedings of the American Mathematical Society, 1996
Let 0 ≤ p ,
openaire   +2 more sources

Grand Furuta inequality and its variant [PDF]

open access: yesJournal of Mathematical Inequalities, 2007
The grand Furuta inequality (GFI) is understood as follows: If positive operators A and B on a Hilbert space satisfy A B 0,A is invertible and t ∈ (0,1) ,t hen A 1−t+r (A r (A − t B p A − t ) s A r ) 1 t+r (pt)s+r holds for p, s 1a ndr t . In this note, we present a short proof of (GFI) which is done by the usual induction on s and the use of the ...
Masatoshi Fujii   +2 more
openaire   +1 more source

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