Results 71 to 80 of about 109 (103)
HYPERCYCLIC OPERATOR WEIGHTED SHIFTS
Bulletin of the Korean Mathematical Society, 2004 A bounded linear operator \(T\) on a Hilbert space \(H\) is said to be hypercyclic if, for some \(x \in H\), the orbit \(\{T^{n}x : n=0,1,2,\dots \}\) is dense in \(H\). In the paper under review, the authors give a characterization for hypercyclicity of a bilateral operator weighted shift \(T\) on the Hilbert space \(L^{2}(K)\).
Hazarika, Munmun, Arora, S. C.
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Journal of Functional Analysis, 2019 We prove the existence of algebras of hypercyclic vectors in three cases: convolution operators, composition operators, and backward shift operators.
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On the Epsilon Hypercyclicity of a Pair of Operators
Journal of Mathematical Extension, 2011 In this paper we prove that if a pair of operators is - hypercyclic for all > 0, then it is topologically ...
B. Yousefi∗, K. Jahedi
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Perturbations of hypercyclic vectors
Journal of Mathematical Analysis and Applications, 2002 A bounded linear operator \(T\) on a separable Banach space \(\mathcal B\) is said to be hypercyclic if there is \(x \in \mathcal B\), also called hypercyclic, such that the elements in the orbit \(\{T^ n x\}_{n\geq 0}\) are dense in \(\mathcal B\). Hypercyclicity is one of the strongest forms of cyclicity. \textit{S. Rolewicz} [Stud. Math. 32, 17--22 (
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Cyclic variations in the dynamics of flu incidence in Azerbaijan, 1976-2000. [PDF]
Epidemiol Infect, 2015 Dimitrov BD, Babayev ES.
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Journal of Functional Analysis, 2003 A (bounded) operator \(T\) on a complex infinite-dimensional separable Banach space \(X\) is said to be hypercyclic if there is a (hypercyclic) vector \(x \in X\) such that its orbit \(O(T,x):=\{x,Tx,T^2x,\dots\}\) is dense in \(X\). The operator \(T\) is called chaotic if it is hypercyclic and the set of periodic points of \(T\) is dense in \(X ...
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EVERY WEAKLY SEQUENTIALLY HYPERCYCLIC SHIFT IS NORM HYPERCYCLIC
Mathematical Proceedings of the Royal Irish Academy, 2005The author show that a bilateral weighted shift on \(\ell^p(\mathbb Z)\) is weakly sequentially supercyclic if and only if it is norm hypercyclic. In particular, it also follows that they are weakly sequentially hypercyclic if and only if they are hypercyclic.
Bès, Juan +2 more
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